Question

Физика. Груз массой 10 кг тянут равномерно по горизонтальной поверхности, прилагая силу, направленную под углом 30 градусов к горизонту. Коэффициент трения равен 0.3. Найти работу этой силы при прохождении телом расстояние 0.5 м?.Решите пожалуйста, напишите полное решение

Answer 1

A=40.7Дж.

m=10кг

а=30°

S=0.5м

u(к.ф.) =0.3

А=?

Решение: F=umg=10*9.8*0.3=29.4

А=FScosA=29.4*0.5*√3/2=12.7(ответ может быть неправильным)

Answer 2

To find the work done by the applied force on the object, we can use the formula:

Work = Force * Distance * cos(theta)

Where: - Force is the magnitude of the applied force - Distance is the distance over which the force is applied - theta is the angle between the force and the direction of motion

In this case, the mass of the object is 10 kg, the applied force is at an angle of 30 degrees to the horizontal, the coefficient of friction is 0.3, and the distance over which the force is applied is 0.5 m.

Calculating the Magnitude of the Applied Force

To calculate the magnitude of the applied force, we need to consider the forces acting on the object. In this case, there are two forces: the applied force and the force of friction.

The force of friction can be calculated using the formula:

Frictional Force = coefficient of friction * Normal Force

The normal force is the force exerted by the surface on the object and is equal to the weight of the object, which can be calculated as:

Normal Force = mass * gravity

Where: - mass is the mass of the object - gravity is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values, we can calculate the normal force and the force of friction.

Calculating the Work Done

Now that we have the magnitude of the applied force, we can calculate the work done using the formula mentioned earlier:

Work = Force * Distance * cos(theta)

Substituting the given values, we can calculate the work done by the applied force.

Let's calculate the values step by step.

Step 1: Calculating the Normal Force

The mass of the object is given as 10 kg. Using the formula for the normal force, we can calculate:

Normal Force = mass * gravity

Normal Force = 10 kg * 9.8 m/s^2

Normal Force = 98 N

Step 2: Calculating the Force of Friction

The coefficient of friction is given as 0.3. Using the formula for the force of friction, we can calculate:

Frictional Force = coefficient of friction * Normal Force

Frictional Force = 0.3 * 98 N

Frictional Force = 29.4 N

Step 3: Calculating the Magnitude of the Applied Force

The applied force is at an angle of 30 degrees to the horizontal. To find the horizontal component of the force, we can use the formula:

Horizontal Component of Force = Force * cos(theta)

Substituting the given values, we can calculate the horizontal component of the force.

Horizontal Component of Force = Force * cos(30 degrees)

Horizontal Component of Force = Force * 0.866

Since the applied force is the only horizontal force acting on the object, it must be equal to the force of friction. Therefore:

Force * 0.866 = 29.4 N

Solving for the force:

Force = 29.4 N / 0.866

Force = 33.9 N

Step 4: Calculating the Work Done

Now that we have the magnitude of the applied force, we can calculate the work done using the formula:

Work = Force * Distance * cos(theta)

Substituting the given values, we can calculate the work done by the applied force.

Work = 33.9 N * 0.5 m * cos(30 degrees)

Work = 33.9 N * 0.5 m * 0.866

Work = 14.7 J

Therefore, the work done by the applied force when the object is pulled over a distance of 0.5 m is 14.7 Joules.