Question

При сжигании бензина в автомобильном двигателе за время t = 2,0 секунды потери энергии составили Q = 0,30 МДж, при этом двигатель развил мощность P = 50 кВт. Определите КПД двигателя.

Answer 1

Решение в приложенном файле

Answer 2

Calculation of Efficiency (КПД) of the Engine

To determine the efficiency (КПД) of the engine, we can use the formula:

КПД = (Useful Output Energy / Input Energy) x 100%

In this case, the useful output energy is the power developed by the engine, and the input energy is the energy supplied by burning the gasoline.

Given: - Time (t) = 2.0 seconds - Energy loss (Q) = 0.30 MJ (Megajoules) - Power developed by the engine (P) = 50 kW (Kilowatts)

To calculate the input energy, we can use the formula:

Input Energy = Power x Time

Substituting the given values:

Input Energy = 50 kW x 2.0 s = 100 kJ (Kilojoules)

Now, we can calculate the efficiency (КПД):

КПД = (Useful Output Energy / Input Energy) x 100%

Substituting the given values:

КПД = (0.30 MJ / 100 kJ) x 100% = 0.3%

Therefore, the efficiency (КПД) of the engine is 0.3%.

Please note that the calculation assumes that all the energy supplied by burning the gasoline is converted into useful output energy, which may not be the case in real-world scenarios.