Question

Дано: t=20°Cm=40кг------------Q-?если что тут вода и мы проходим удельная теплота парообразования 8 класси сказано что нужно повысить температуру чтобы было 100°С.Помогите пожалуйста ​

Answer 1

Дано:

t1= 20°C

t2= 100°C

m= 40 кг

с= 4 200 Дж/кг×°С

_________________

Q-?

Розв'язання:

Q= cm(t2-t1)

Q= 4200×40×(100-20)= 13 44×10⁴ Дж

Відповідь:. Q= 13,44 МДж

Answer 2

Calculation of Heat Energy Required to Raise the Temperature of Water

To calculate the heat energy required to raise the temperature of water from 20°C to 100°C, we can use the formula:

Q = m * c * ΔT

Where: - Q is the heat energy (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, the mass of the water is given as 40 kg and the initial temperature is 20°C. We need to find the heat energy required to raise the temperature to 100°C.

First, let's find the change in temperature:

ΔT = final temperature - initial temperature = 100°C - 20°C = 80°C

Next, we need to find the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C or 4180 J/kg°C.

Now, we can substitute the values into the formula:

Q = m * c * ΔT = 40 kg * 4180 J/kg°C * 80°C

Calculating this expression will give us the heat energy required to raise the temperature of water from 20°C to 100°C.

Please note that the specific heat capacity of water is given in joules per kilogram per degree Celsius, so we need to ensure that the units are consistent in the calculation.

Let's calculate the heat energy:

Q = 40 kg * 4180 J/kg°C * 80°C = 13,376,000 J

Therefore, the heat energy required to raise the temperature of 40 kg of water from 20°C to 100°C is 13,376,000 joules.

Please let me know if you need any further assistance!