Question

Голка швацької машини коливається з періодом 0,25 с. Знайдіть частоту коливання голки. Скільки коливань здійснить голка за 2 хвилини?

Answer 1

Відповідь:

T=0,25c

t=2хв=120c

ν-?

ν=1/T=1/0,25=4гц

N=ν*t=4*120=480коливань

або

N=t/T=120/0,25=480коливань

Пояснення:

Answer 2

Calculation of Needle Frequency and Number of Oscillations

To find the frequency of the needle's oscillation, we can use the formula:

Frequency (f) = 1 / Period (T)

Given that the period (T) of the needle's oscillation is 0.25 seconds, we can calculate the frequency as follows:

f = 1 / 0.25 = 4 Hz

Therefore, the frequency of the needle's oscillation is 4 Hz.

To determine the number of oscillations the needle will complete in 2 minutes, we need to convert the time from minutes to seconds. Since there are 60 seconds in a minute, 2 minutes is equal to 2 * 60 = 120 seconds.

Now, we can calculate the number of oscillations using the formula:

Number of oscillations = Frequency (f) * Time (t)

Substituting the values, we have:

Number of oscillations = 4 Hz * 120 s = 480 oscillations

Therefore, the needle will complete 480 oscillations in 2 minutes.

Please note that the above calculations are based on the given information and assumptions.