Question

Карусель равномерно движется по окружности радиусом 2 м. Определите период вращения, если скорость равна равно 2 м/с. Срочно РЕШЕНИЕ​

Answer 1

Ответ: 6,28с

Объяснение:

Дано:

R=2м

V=2м/с

=======

Т-?

T=2πω

ω=V/R=2/2=1рад/с

T=2*3,14/1=6,28с

Answer 2

Problem Analysis

We are given that a carousel moves uniformly in a circular path with a radius of 2 meters. The speed of the carousel is given as 2 m/s. We need to determine the period of rotation.

Solution

The period of rotation is the time taken for the carousel to complete one full revolution. It can be calculated using the formula:

Period = Circumference / Speed

The circumference of a circle can be calculated using the formula:

Circumference = 2 * π * Radius

Substituting the given values, we can calculate the period.

Calculation

The radius of the carousel is given as 2 meters. Therefore, the circumference can be calculated as:

Circumference = 2 * π * 2 = 4π meters

The speed of the carousel is given as 2 m/s. Therefore, the period can be calculated as:

Period = Circumference / Speed = (4π meters) / (2 m/s) = 2π seconds

Answer

The period of rotation for the carousel is 2π seconds.

Verification

To verify the answer, we can check if the calculated period satisfies the given conditions. According to the problem statement, the speed of the carousel is 2 m/s. Since the circumference of the circle is 4π meters, it will take 2π seconds for the carousel to complete one full revolution. Therefore, the calculated period of 2π seconds is correct.