Вопрос задан 18.06.2023 в 10:01. Предмет Физика. Спрашивает Алмаз Жумабек.

час обертання Землі навколо своєї осі дорівнює 24 години.Обчисліть лінійну швидкість обертання

точок поверхні землі на екваторі. З якою лінійною швидкістю рухається земля навколо сонця? Радіус землі 6378 км. Радіус земної орбіти 1,5×10⁸км.​
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Бабаева Виктория.

Ответ:

v = 2pR / T

v = 6.28 * 6378 / 24

v = 1668.91 км

v1 = 2pR / T

v1 = 1,5×10⁸ * 6.28 / 365 = 2580821.91781 км/день

0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Linear Speed of Earth's Rotation at the Equator

The time taken by the Earth to complete one full rotation on its axis is 24 hours. To calculate the linear speed of points on the Earth's surface at the equator, we need to determine the circumference of the Earth at the equator and divide it by the time taken for one rotation.

The formula to calculate the circumference of a circle is given by:

Circumference = 2 * π * radius

Given that the radius of the Earth is 6378 km, we can substitute this value into the formula to find the circumference at the equator.

Circumference = 2 * π * 6378 km

Now, we can calculate the linear speed of points on the Earth's surface at the equator by dividing the circumference by the time taken for one rotation.

Linear Speed = Circumference / Time taken for one rotation

Substituting the values, we get:

Linear Speed = (2 * π * 6378 km) / 24 hours

To convert the linear speed from kilometers per hour to meters per second, we need to multiply it by 1000/3600.

Linear Speed = (2 * π * 6378 km) / 24 hours * (1000 m / 1 km) * (1 hour / 3600 s)

Let's calculate the value using the given formula:

Linear Speed = (2 * π * 6378 km) / 24 hours * (1000 m / 1 km) * (1 hour / 3600 s)

Linear Speed = 1674.4 m/s

Therefore, the linear speed of points on the Earth's surface at the equator is approximately 1674.4 meters per second.

Linear Speed of Earth's Orbit around the Sun

To calculate the linear speed of the Earth's orbit around the Sun, we need to determine the circumference of the Earth's orbit and divide it by the time taken for one revolution around the Sun.

The formula to calculate the circumference of a circle is the same as before:

Circumference = 2 * π * radius

Given that the radius of the Earth's orbit is 1.5 × 10^8 km, we can substitute this value into the formula to find the circumference.

Circumference = 2 * π * 1.5 × 10^8 km

Now, we can calculate the linear speed of the Earth's orbit around the Sun by dividing the circumference by the time taken for one revolution.

Unfortunately, I couldn't find the exact time taken for one revolution around the Sun in the search results. However, the average orbital period of the Earth around the Sun is approximately 365.25 days. To calculate the linear speed, we need to convert this time into seconds.

Time taken for one revolution = 365.25 days * 24 hours * 60 minutes * 60 seconds

Let's calculate the value using the given formula:

Time taken for one revolution = 365.25 days * 24 hours * 60 minutes * 60 seconds

Time taken for one revolution = 31,557,600 seconds

Now, we can calculate the linear speed of the Earth's orbit around the Sun by dividing the circumference by the time taken for one revolution.

Linear Speed = Circumference / Time taken for one revolution

Substituting the values, we get:

Linear Speed = (2 * π * 1.5 × 10^8 km) / 31,557,600 seconds

To convert the linear speed from kilometers per second to meters per second, we need to multiply it by 1000.

Linear Speed = (2 * π * 1.5 × 10^8 km) / 31,557,600 seconds * (1000 m / 1 km)

Let's calculate the value using the given formula:

Linear Speed = (2 * π * 1.5 × 10^8 km) / 31,557,600 seconds * (1000 m / 1 km)

Linear Speed = 29,292.5 m/s

Therefore, the linear speed of the Earth's orbit around the Sun is approximately 29,292.5 meters per second.

0 0

Похожие вопросы

Топ вопросов за вчера в категории Физика

Последние заданные вопросы в категории Физика

Задать вопрос