Question

8. Определите магнитный поток Ф через контур площадью 10 дм’в однородном магнитном поле с индукцией В, равной 40 Tл, если угол между вектором индукции Ви нормалью к плоскости контура равен 60°.

Answer 1

Объяснение:

Ф = BScosa.

................

Answer 2

Calculation of Magnetic Flux through a Contour

To calculate the magnetic flux (Φ) through a contour in a uniform magnetic field, we can use the formula:

Φ = B * A * cos(θ)

Where: - Φ is the magnetic flux through the contour, - B is the magnetic field induction (also known as magnetic field strength) in Tesla (T), - A is the area of the contour in square meters (m²), - θ is the angle between the magnetic field vector (B) and the normal to the plane of the contour.

In this case, we are given: - The area of the contour is 10 dm², which is equal to 0.1 m². - The magnetic field induction (B) is 40 Tl. - The angle (θ) between the magnetic field vector (B) and the normal to the plane of the contour is 60°.

Now, let's calculate the magnetic flux through the contour using the given values:

Φ = B * A * cos(θ)

Φ = 40 Tl * 0.1 m² * cos(60°)

Using the trigonometric identity cos(60°) = 0.5, we can simplify the equation:

Φ = 40 Tl * 0.1 m² * 0.5

Φ = 2 Tl * m²

Therefore, the magnetic flux through the contour is 2 Tl * m².

Please note that the source provided a snippet that does not seem to be directly related to the calculation of magnetic flux. However, the formula and the calculations provided above are based on the well-established principles of electromagnetism.