Question

1. В алюминиевом посуде массой 0,5 кг находится I кг воды при температуре 10 ºС. Какая энергия выделится при образовании из этой воды льда при температуре 0 °С?​

Answer 1

Ответ:

50 гр керосина * 43.1 МДж/кг = 2.155 МДж.

КПД 50% - значит на всё про всё у нас 1.0775 МДж.

Сначала лёд надо перевести в воду: 2 кг * 3.33*10^5 Дж/кг = 0.666 МДж.

Осталось 0.4115 МДж = 411500 Дж.

Теперь считаем теплоёмкость системы, состоящей из полкило алюминия и 2 кг воды: (0.5*920 + 2*4200) = 8860 Дж/градус.

Делим 411500/8860 = 46.4 градуса Цельсия.

Ответ:46.4 градуса Цельсия

Объяснение:

Answer 2

Calculation of Energy Released during Formation of Ice

To calculate the energy released during the formation of ice from water, we can use the formula:

Q = m * L

Where: - Q is the energy released or absorbed (in joules) - m is the mass of the substance (in kilograms) - L is the specific latent heat of fusion (in joules per kilogram)

In this case, we have an aluminum vessel with a mass of 0.5 kg containing 1 kg of water at a temperature of 10°C. We want to find the energy released when this water freezes into ice at 0°C.

To calculate the energy released, we need to know the specific latent heat of fusion for water. The specific latent heat of fusion for water is approximately 334,000 J/kg.

Using the formula mentioned above, we can calculate the energy released:

Q = m * L = 1 kg * 334,000 J/kg = 334,000 J

Therefore, 334,000 joules of energy will be released when 1 kg of water freezes into ice at 0°C.

Please note that this calculation assumes that there is no heat exchange with the surroundings and that the process occurs at constant pressure.

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