Question

распространяющийся в воздухе световой луч падает на поверхность жидкости под углом 40 градусов. угол преломления равен 24 градусам. чему будет равен угол преломления при падении луча на поверхность той же самой жидкости под углом 80 градусов?

Answer 1

Ответ:36°

Объяснение:

Answer 2

Calculation of Refracted Angle

To calculate the refracted angle when a light ray passes from air to a liquid, we can use Snell's law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the velocities of light in the two media.

Mathematically, Snell's law can be expressed as:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Where: - n₁ is the refractive index of the medium the light is coming from (in this case, air) - θ₁ is the angle of incidence - n₂ is the refractive index of the medium the light is entering (in this case, the liquid) - θ₂ is the angle of refraction

In this case, we are given: - The angle of incidence (θ₁) is 40 degrees. - The angle of refraction (θ₂) is 24 degrees.

We need to find the refracted angle (θ₂') when the light ray falls on the same liquid surface at an angle of 80 degrees (θ₁').

To find θ₂', we can rearrange Snell's law as follows:

θ₂' = arcsin((n₁ * sin(θ₁')) / n₂)

Let's substitute the given values into the equation and calculate θ₂':

θ₂' = arcsin((n₁ * sin(θ₁')) / n₂) = arcsin((n₁ * sin(80)) / n₂)

Unfortunately, the specific refractive indices for the air and liquid are not provided in the question. Without this information, we cannot calculate the exact value of θ₂'.