Question

В электрическую сеть переменного тока с действующим значением напряжения 220 В (вольт) включены последовательно два элемента: сопротивление R и емкость C. Определить действующее значение напряжения на емкости, если действующее значение напряжения на сопротивлении равно 211 вольт. Ответ выразить в вольтах и округлить до целого числа.

Answer 1

Ответ:

Объяснение:

Дано:

U = 220 В

Ur = 211 В

_________

Uc - ?

Из формулы:

U = √ ( (Ur)² + (Uc)² )

находим:

U² = (Ur)² + (Uc)²

Uc = √ ( U² - (Ur)² )

Uc = √ ( 220² - 211² ) ≈ 62 B

Answer 2

Calculating Voltage on the Capacitor in an AC Circuit

In an electrical circuit with an alternating current (AC) and a voltage of 220V, a resistor (R) and a capacitor (C) are connected in series. The voltage across the resistor is 211V. We need to determine the voltage across the capacitor.

To calculate the voltage across the capacitor, we can use the relationship between the voltage, resistance, and capacitance in an AC circuit.

Step 1: Calculate the Voltage on the Capacitor

The voltage across the resistor (Vr) is given as 211V. The voltage across the capacitor (Vc) can be calculated using the following formula:

Vc = √(V^2 - Vr^2)

Where: - V is the total voltage in the circuit (220V) - Vr is the voltage across the resistor (211V)

Let's calculate the voltage across the capacitor using the given values:

Vc = √(220^2 - 211^2)

Vc ≈ 116V

The voltage across the capacitor is approximately 116 volts.

This calculation is based on the relationship between voltage, resistance, and capacitance in an AC circuit.