Question

К пружине подвесили груз 400г на сколько растянулась пружина, если её жесткость 40н/м?​

Answer 1

Ответ:

0.1 метр

Объяснение:

x=F/k=mg/k=0.400*10/40=0.1метр

Answer 2

Calculation of the Spring Extension

To calculate the extension of a spring when a weight is suspended from it, we can use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the extension or compression of the spring. The formula for Hooke's Law is:

F = k * x

Where: - F is the force applied to the spring (in newtons) - k is the spring constant or stiffness of the spring (in newtons per meter) - x is the extension or compression of the spring (in meters)

In this case, we are given the following information: - The weight suspended from the spring is 400 grams, which is equivalent to 0.4 kilograms. - The spring constant or stiffness of the spring is 40 newtons per meter.

To find the extension of the spring, we need to convert the weight from grams to kilograms and then use Hooke's Law to calculate the extension.

Let's calculate the extension of the spring:

F = k * x 0.4 kg * 9.8 m/s^2 = 40 N/m * x

Simplifying the equation:

3.92 N = 40 N/m * x

Now, we can solve for x:

x = 3.92 N / 40 N/m x = 0.098 meters

Therefore, the spring will stretch by approximately 0.098 meters when a 400-gram weight is suspended from it.