Question

Кулька 1 масою 20 г, що висить на нитці, має заряд 4 мкКл. Знизу дуже здалеку до неї підносять кульку 2, яка має заряд -8 мкКл. На яку відстань слід піднести куль- ку 2, щоб сила натягу нитки збільшилася вдвічі? Пж пж срочно !!!!!!​

Answer 1

Ответ:

См. ниже

Объяснение:

Answer 2

Electric Charge and Force Calculation

To calculate the distance at which the force of tension in the string will double when bringing the second sphere close to the first one, we can use Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for the force between two charges is given by:

F = k * |q1 * q2| / r^2

Where: - F is the force between the charges - k is Coulomb's constant (8.9875 x 10^9 N m^2/C^2) - q1 and q2 are the magnitudes of the charges - r is the distance between the charges

Calculating the Distance

Given: - Charge of sphere 1 (q1) = 4 µC - Charge of sphere 2 (q2) = -8 µC - Initial mass of sphere 1 = 20 g

The force of tension in the string can be related to the gravitational force acting on the sphere:

F_tension = F_gravity

The force of gravity can be calculated using the formula:

F_gravity = m * g

Where: - m is the mass of the sphere - g is the acceleration due to gravity (9.81 m/s^2)

Solution

First, we need to calculate the force of tension in the string when only sphere 1 is present. Then, we can calculate the distance at which the force of tension will double when sphere 2 is brought close to sphere 1.

Let's proceed with the calculations.