Question

СРОЧНО сила воздействия на лопату равна 500Нширина прямоугольного полотна лопаты-25см, толщина 0,5 ммвычисли давление режущего края лопаты на землюg=9,8Н/кгответ округли до целого числаp≈ МПа​

Answer 1

Ответ:

Объяснение:

F = 500 H

a = 25 см

b = 0,5 мм

p - ?

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p = F / S; S = a·b ⇒ p = F / (a·b)

p = 500 / (25·10⁻²·5·10⁻⁴) = 500 / (125·10⁻⁶) = 4·10⁶ Па  или  4 МПа

Answer 2

Calculating Pressure Exerted by the Blade of a Shovel

To calculate the pressure exerted by the blade of the shovel on the ground, we can use the formula:

Pressure (P) = Force (F) / Area (A)

First, we need to calculate the area of the blade that comes into contact with the ground.

Given: - Force (F) = 500 N - Width of the rectangular blade = 25 cm = 0.25 m - Thickness of the blade = 0.5 mm = 0.0005 m - Acceleration due to gravity (g) = 9.8 m/s^2

Calculating the Area of the Blade

The area (A) of the blade in contact with the ground can be calculated as the product of its width and thickness.

Area (A) = Width × Thickness

Substituting the given values: Area (A) = 0.25 m × 0.0005 m

Calculating the area: Area (A) = 0.000125 m^2

Calculating the Pressure

Now, we can use the formula to calculate the pressure exerted by the blade on the ground.

Pressure (P) = Force / Area

Substituting the given values: Pressure (P) = 500 N / 0.000125 m^2

Calculating the pressure: Pressure (P) ≈ 4,000,000 Pa

Rounding the pressure to the nearest whole number: Pressure (P) ≈ 4 MPa

So, the pressure exerted by the cutting edge of the shovel on the ground is approximately 4 MPa.