Question

Щоб рівномірно рухати по столу тіло масою 3 кг, треба прикласти горизонтальну силу 6H. Чому дорівнює кофіціент тертя ковзання між тілом і столом​

Answer 1

Ответ:

P1v1=p2v2 -итп(изотермический процесс) p2v2/p1 2700кг/м3*0,1м3 / 900кг/м3=0,3 м3

Answer 2

Calculation of the Coefficient of Friction

To determine the coefficient of friction between the body and the table, we can use the given information about the force applied and the mass of the body. The coefficient of friction can be calculated using the formula:

Coefficient of Friction (μ) = Force of Friction (F) / Normal Force (N)

In this case, the force of friction is equal to the horizontal force applied to move the body, which is given as 6H. The normal force is equal to the weight of the body, which can be calculated using the formula:

Normal Force (N) = Mass (m) * Acceleration due to Gravity (g)

Given that the mass of the body is 3 kg, we can substitute the values into the formulas to calculate the coefficient of friction.

Step 1: Calculate the normal force: Normal Force (N) = Mass (m) * Acceleration due to Gravity (g)

Substituting the values: N = 3 kg * 9.8 m/s^2 (acceleration due to gravity)

Step 2: Calculate the coefficient of friction: Coefficient of Friction (μ) = Force of Friction (F) / Normal Force (N)

Substituting the values: μ = 6H / N

Now, let's calculate the coefficient of friction using the given information.

Step 1: Calculate the normal force: N = 3 kg * 9.8 m/s^2 = 29.4 N

Step 2: Calculate the coefficient of friction: μ = 6H / N

Since the value of H is not provided in the question, we cannot calculate the exact value of the coefficient of friction without this information.