Question

Задача 1. Люстра подвешена к потолку. Её масса равна 5,5 кг. С какой силой люстра действует на потолок? Как называется эта сила?

Answer 1

Ответ:

55 Н

Объяснение:

на люстру действует сила тяжести, равная F = m(5,5кг)*g(10м/$c^{2}$) = 55 Н. Но люстра не падает, потому что ее держит потолок, значит потолок держит ее с такой же силой 55Н

Answer 2

Ответ:

дано: m= 5.5,

g = 10 м/с^2 - ускорение свободного падения.                

решение F = : m * g = 5.5 * 10 =55 Ньютон.

Ответ: люстра действует на потолок с силой, равной 40 Ньютон

Объяснение: F = : m * g

Answer 3

Calculation of the Force Exerted by the Chandelier

To calculate the force exerted by the chandelier on the ceiling, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the chandelier is not accelerating, so the acceleration is zero. Therefore, the force exerted by the chandelier on the ceiling is zero.

The force exerted by the chandelier on the ceiling is also known as the normal force. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force exerted by the ceiling on the chandelier is equal in magnitude but opposite in direction to the weight of the chandelier.

Therefore, the force exerted by the chandelier on the ceiling is zero, and the name of this force is the normal force.

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