Question

Определите напряжение на концах железного проводника длиной 15 м и площадью поперечного сечения 0,3 мм2, при котором сила тока в проводнике будет равна 100 мА

Answer 1

Ответ:

0.5

Объяснение:

R=rl/s=0,1*15/0.3=5

U=I*R=0.1*5=0.5 вольт

Answer 2

Calculating Voltage on the Conductor

To calculate the voltage on the ends of the iron conductor, we can use Ohm's law, which states that voltage (V) is equal to the product of current (I) and resistance (R), i.e., V = I * R. The resistance of the conductor can be calculated using the formula R = ρ * (L/A), where ρ is the resistivity of the material, L is the length of the conductor, and A is the cross-sectional area of the conductor.

Given: - Length of the conductor (L) = 15 m - Cross-sectional area of the conductor (A) = 0.3 mm^2 - Current (I) = 100 mA = 0.1 A

Calculation Steps

1. Convert the cross-sectional area from mm^2 to m^2. 2. Calculate the resistance using the formula R = ρ * (L/A). 3. Use Ohm's law to calculate the voltage using the formula V = I * R.

Calculation

1. Convert the cross-sectional area from mm^2 to m^2: - A = 0.3 mm^2 = 0.3 * 10^-6 m^2 = 3 * 10^-7 m^2

2. Calculate the resistance: - Using the resistivity of iron (ρ = 9.71 * 10^-8 Ωm) - R = ρ * (L/A) = 9.71 * 10^-8 * (15 / (3 * 10^-7)) = 0.485 Ω

3. Calculate the voltage: - Using Ohm's law (V = I * R): - V = 0.1 * 0.485 = 0.0485 V

The voltage on the ends of the iron conductor, at which the current in the conductor will be 100 mA, is approximately 0.0485 volts.