Question

ДАЮ 50 БАЛЛОВ, ПОМОГИТЕ,ПОЖАЛУЙСТА! В калориметре находятся лёд и вода с равными массами m1=500 г при t1=0°C.Какая температура установится в калориметре после добавления в него m2=1 кг воды при температуреt2=50°C?Теплоемкостью калорииетоа и тепловыми потерями пренебречь. Удельная теплоёмкость воды равна 4,2кДж/(кг°С),удельная теплота плавления льда равна 340 кДж/кг.ответ выразить в градусах Цельсия и округлить до десятых долей​

Answer 1

Ответ:

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Объяснение:

Answer 2

Calculation of Final Temperature in the Calorimeter

To calculate the final temperature in the calorimeter after adding water, we can use the principle of conservation of energy. The heat gained by the water should be equal to the heat lost by the ice and the water in the calorimeter.

Let's break down the steps to solve this problem:

1. Calculate the heat gained by the water: - The heat gained by the water can be calculated using the formula: Q = m * c * ΔT, where Q is the heat gained, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. - In this case, the mass of the water is 1 kg (m2 = 1000 g) and the initial temperature is 50°C (t2 = 50°C). - The specific heat capacity of water is 4.2 kJ/(kg°C). - Therefore, the heat gained by the water is: Q2 = m2 * c * ΔT2.

2. Calculate the heat lost by the ice and the water in the calorimeter: - The heat lost by the ice and the water in the calorimeter can be calculated using the formula: Q = m * L, where Q is the heat lost, m is the mass of the substance, and L is the specific latent heat. - In this case, the mass of the ice is equal to the mass of the water in the calorimeter, which is 500 g (m1 = 500 g). - The specific latent heat of fusion for ice is 340 kJ/kg. - Therefore, the heat lost by the ice and the water in the calorimeter is: Q1 = m1 * L.

3. Apply the principle of conservation of energy: - According to the principle of conservation of energy, the heat gained by the water should be equal to the heat lost by the ice and the water in the calorimeter. - Therefore, we can equate the two equations: Q2 = Q1.

4. Solve the equation for the final temperature: - Rearrange the equation to solve for the change in temperature: ΔT2 = Q1 / (m2 * c). - Substitute the values into the equation: ΔT2 = (m1 * L) / (m2 * c). - Calculate the change in temperature: ΔT2 = (500 g * 340 kJ/kg) / (1000 g * 4.2 kJ/(kg°C)).

5. Calculate the final temperature: - The final temperature can be calculated by subtracting the change in temperature from the initial temperature of the water in the calorimeter: t_final = t2 - ΔT2.

Let's calculate the final temperature using the given values:

- m1 = 500 g - t1 = 0°C - m2 = 1 kg - t2 = 50°C - c = 4.2 kJ/(kg°C) - L = 340 kJ/kg

Calculation:

1. Calculate the change in temperature: - ΔT2 = (500 g * 340 kJ/kg) / (1000 g * 4.2 kJ/(kg°C))

2. Calculate the final temperature: - t_final = t2 - ΔT2

Let's perform the calculations: