Question

(В случае : копии, спама, неполного ответа, кидаю жалобу) Стрела вылетает из арбалета вертикально вверх со скоростью 15 м/с. Масса стрелы 50 г. А) Определите начальную кинетическую энергию стрелы В) Вычислите значение максимальной высоты подъема С) Как изменится высота подъема стрелы вдвое большей массы?​

Answer 1

Ответ:

56,25

11.25

1

Объяснение:

v=15
m=50g=5×10^-2 kg
___________/

1)

E=mv^2 /2=56,25

2)

a=g=10
H=v^2/ 2g=11.25

3)

M=2m
mg=ma
Mg=Ma

g=a
V/v=1

Answer 2

Calculation of Initial Kinetic Energy of the Arrow

To determine the initial kinetic energy of the arrow, we can use the formula for kinetic energy:

Kinetic Energy (KE) = (1/2) * mass * velocity^2

Given that the mass of the arrow is 50 grams (0.05 kg) and the velocity is 15 m/s, we can substitute these values into the formula:

KE = (1/2) * 0.05 kg * (15 m/s)^2

Simplifying the equation:

KE = 0.5 * 0.05 kg * 225 m^2/s^2

KE = 5.625 J

Therefore, the initial kinetic energy of the arrow is 5.625 Joules. [[1]]

Calculation of Maximum Height Reached by the Arrow

To calculate the maximum height reached by the arrow, we can use the principle of conservation of mechanical energy. At the maximum height, all of the initial kinetic energy is converted into potential energy.

Potential Energy (PE) = mass * gravity * height

Given that the mass of the arrow is 50 grams (0.05 kg) and the acceleration due to gravity is approximately 9.8 m/s^2, we can substitute these values into the formula:

PE = 0.05 kg * 9.8 m/s^2 * height

Since the initial kinetic energy is equal to the potential energy at the maximum height, we can equate the two:

KE = PE

5.625 J = 0.05 kg * 9.8 m/s^2 * height

Simplifying the equation:

height = 5.625 J / (0.05 kg * 9.8 m/s^2)

height ≈ 11.47 meters

Therefore, the maximum height reached by the arrow is approximately 11.47 meters. [[2]]

Effect of Doubling the Mass on the Height Reached by the Arrow

If we double the mass of the arrow while keeping the other variables constant, we can determine the effect on the height reached by the arrow.

Let's assume the new mass of the arrow is 100 grams (0.1 kg). Using the same formula as before:

PE = 0.1 kg * 9.8 m/s^2 * height

Since the initial kinetic energy is still equal to the potential energy at the maximum height, we can equate the two:

KE = PE

5.625 J = 0.1 kg * 9.8 m/s^2 * height

Simplifying the equation:

height = 5.625 J / (0.1 kg * 9.8 m/s^2)

height ≈ 0.57 meters

Therefore, if we double the mass of the arrow, the height reached by the arrow will be approximately 0.57 meters. [[3]]

Please note that these calculations assume ideal conditions and do not take into account factors such as air resistance.