Question

Маса поїзда – 1200 т. Чому дорівнює сила тяги під час рівномірного прямолінійного руху, якщо сила тертя складає 0,02 його ваги?​

Answer 1

Ответ: 240кН

Объяснение:

Дано:

m=1200т=1200000кг

μ=0,02

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Fт-?

При равномерном движении сила тяги равна силе сопротивления.

Поскольку другие виды сопротивления не указаны, будем считать, что действует только сила трения.

Fтр=Fтяж*μ=mgμ=1200000*10*0,02=240000Н=240кН

Answer 2

Calculation of Tractive Force

To calculate the tractive force during uniform rectilinear motion, we need to consider the weight of the train and the force of friction acting against it. In this case, the weight of the train is given as 1200 tons, and the force of friction is stated to be 0.02 times its weight.

The tractive force can be calculated by subtracting the force of friction from the weight of the train. Let's perform the calculation:

Weight of the train = 1200 tons

Force of friction = 0.02 * weight of the train

Tractive force = Weight of the train - Force of friction

Tractive force = 1200 tons - (0.02 * 1200 tons)

Tractive force = 1200 tons - 24 tons

Tractive force = 1176 tons

Therefore, the tractive force during uniform rectilinear motion, when the force of friction is 0.02 times the weight of the train, is 1176 tons.

Please note that the above calculation is based on the given information and assumptions. If there are any additional factors or considerations, they should be taken into account for a more accurate calculation.