Question

Маса потягу – 1200 т. Чому дорівнює сила тяги під час рівномірного прямолінійного руху, якщо сила тертя складає 0,02 його ваги?

Answer 1

Так як рух рівномірний, то F тяги = F тертя.


Fтер=0,02 mg


Fтяги=0,02mg=0,02*1000 000 кг*10 Н/кг=200 000 Н=200 кН.

Answer 2

Calculation of the Tractive Force

To calculate the tractive force during uniform rectilinear motion, we need to consider the mass of the train and the force of friction acting against it.

Given: - Mass of the train = 1200 t (tonnes) - Force of friction = 0.02 times its weight

To find the tractive force, we need to determine the weight of the train and then calculate the force of friction.

Determining the Weight of the Train

The weight of an object can be calculated using the formula:

Weight = Mass x Acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Converting the mass of the train from tonnes to kilograms: - 1 tonne = 1000 kg

Therefore, the mass of the train in kilograms is: - Mass = 1200 t x 1000 kg/t = 1,200,000 kg

Calculating the weight of the train: - Weight = Mass x Acceleration due to gravity = 1,200,000 kg x 9.8 m/s^2

Calculating the Force of Friction

The force of friction can be calculated using the formula:

Force of Friction = Coefficient of Friction x Normal Force

In this case, the coefficient of friction is given as 0.02 times its weight.

Substituting the weight of the train into the formula: - Force of Friction = 0.02 x Weight

Calculating the Tractive Force

The tractive force is equal to the force of friction acting against the train.

Therefore, the tractive force during uniform rectilinear motion is equal to the force of friction, which is calculated as 0.02 times the weight of the train.

Let's calculate the tractive force using the given values.

Calculation:

Weight = 1,200,000 kg x 9.8 m/s^2 Force of Friction = 0.02 x Weight Tractive Force = Force of Friction

Now, let's calculate the tractive force using the given values:

Weight = 1,200,000 kg x 9.8 m/s^2 = 11,760,000 N Force of Friction = 0.02 x Weight = 0.02 x 11,760,000 N = 235,200 N Tractive Force = Force of Friction = 235,200 N

Therefore, the tractive force during uniform rectilinear motion, when the force of friction is 0.02 times its weight, is 235,200 Newtons.

Please note that the above calculation assumes that the force of friction remains constant throughout the motion and that there are no other external forces acting on the train.