Question

Аккумулятор даёт напряжение 12 В и питает внешнюю цепь сопротивлением 5 Ом. Какая работа совершается в нём за 0, 5 часа?

Answer 1

Відповідь:

5184Дж

Пояснення:

А=U*I*t⇒U²*t/R⇒12²*1800/5=5184 Дж

0,5 часа=1800 с

Answer 2

Ответ:

2 часа

объяснения и решения:

нету

Answer 3

Calculation of Work Done by the Battery

To calculate the work done by the battery, we can use the formula:

Work = Voltage x Current x Time

Given that the battery provides a voltage of 12 V and powers an external circuit with a resistance of 5 Ω, we can calculate the current flowing through the circuit using Ohm's Law:

Current = Voltage / Resistance

Substituting the given values, we have:

Current = 12 V / 5 Ω = 2.4 A

Now, we can calculate the work done by the battery over a time of 0.5 hours (or 30 minutes):

Time = 0.5 hours = 30 minutes

Converting the time to seconds:

Time = 30 minutes x 60 seconds/minute = 1800 seconds

Substituting the values into the formula:

Work = 12 V x 2.4 A x 1800 seconds

Calculating the work:

Work = 51,840 Joules

Therefore, the work done by the battery over a period of 0.5 hours is 51,840 Joules.