Question

аллюминиевый шар с полостью в воздухе весит 48,6 Н , а в воде 46,6 Н . определите объем шара и объём полости внутри его

Answer 1

Ответ:

Cила Архимеда, действующая на шарик в воде равна разности веса шарика в воздухе и в воде, т.е. Fa = F1 - F2 = 48,6 H - 46,6 H = 2 H

C другой стороны сила Архимеда Fa = ρgVт, откуда Vт = Fa / ρg

Vт = 2 Н / (1000 кг/м³ * 10 м/с²) = 0,0002 м³

mа =  ρa*V

Вес шарика в воздухе F1 = mg = ρа*g*V, V = F1 / (ρa*g)

V = 48,6 H / (2700 кг/м³ * 10 м/с²) = 0,0018 м³

V > Vт - шарик внутри не полый.

Answer 2

Calculating the Volume of the Aluminum Sphere and the Hollow Inside

To calculate the volume of the aluminum sphere and the hollow inside, we can use the difference in the weight of the sphere in air and in water. The difference in weight is due to the buoyant force acting on the sphere when it is submerged in water.

The buoyant force can be calculated using the formula: Buoyant force = Weight in air - Weight in water

The buoyant force is equal to the weight of the water displaced by the sphere, which is also equal to the weight of the sphere when it is submerged. Using this information, we can calculate the volume of the sphere and the hollow inside.

Calculating the Volume of the Sphere

The weight of the aluminum sphere in air is 48.6 N, and in water, it is 46.6 N. Using the buoyant force formula, we can calculate the volume of the sphere.

Weight in air = 48.6 N Weight in water = 46.6 N

The buoyant force can be calculated as: Buoyant force = Weight in air - Weight in water

Buoyant force = 48.6 N - 46.6 N = 2 N

The buoyant force is equal to the weight of the water displaced by the sphere, which is also equal to the weight of the sphere when it is submerged. Using the buoyant force, we can calculate the volume of the sphere.

Calculating the Volume of the Hollow Inside

The volume of the hollow inside the sphere can be calculated by subtracting the volume of the solid sphere from the total volume of the sphere.

Let's denote: - V_total as the total volume of the sphere - V_solid as the volume of the solid sphere

The volume of the hollow inside can be calculated as: Volume of hollow = V_total - V_solid

We can use the formula for the volume of a sphere: V = (4/3) * π * r^3

Where: - V = volume - π is approximately 3.14159 - r is the radius of the sphere

By solving for the radius and using it to calculate the volumes, we can find the volume of the sphere and the hollow inside.

Conclusion

By using the difference in weight of the aluminum sphere in air and in water, we can calculate the volume of the sphere and the hollow inside. This information will allow us to determine the dimensions of the sphere and the hollow inside.