Question

❗️ФИЗИКА 10 класс❗️ У идеальной тепловой машины КПД равен 30% . Чему равна температура нагревателя, если температура холодильника 27С

Answer 1

Ответ: Тн=428,6К=155,6°С

Объяснение:

Дано:

η=30%=0,3

tx=27°C=300К

----------------------

Тн-?

η=(Тн-Тх)/Тн

Подставим значения и получим:

(Тн-300)/Тн=0,3

0,7Тн=300

Тн=428,6К=155,6°С

Answer 2

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Answer 3

Efficiency of an Ideal Heat Engine

The efficiency of an ideal heat engine is given by the formula:

Efficiency = 1 - (Tc/Th)

where: - Efficiency is the efficiency of the heat engine, - Tc is the temperature of the cold reservoir (in Kelvin), and - Th is the temperature of the hot reservoir (in Kelvin).

In this case, we are given that the efficiency of the heat engine is 30%. We are also given the temperature of the cold reservoir, which is 27°C. To find the temperature of the hot reservoir, we need to convert the temperature from Celsius to Kelvin.

Converting Celsius to Kelvin

To convert a temperature from Celsius to Kelvin, we use the formula:

Kelvin = Celsius + 273.15

Using this formula, we can convert the temperature of the cold reservoir from Celsius to Kelvin:

Tc = 27 + 273.15 = 300.15 K

Calculating the Temperature of the Hot Reservoir

Now that we have the efficiency of the heat engine and the temperature of the cold reservoir in Kelvin, we can rearrange the efficiency formula to solve for the temperature of the hot reservoir:

Efficiency = 1 - (Tc/Th)

Substituting the given values:

0.30 = 1 - (300.15/Th)

Simplifying the equation:

0.30 = 1 - 300.15/Th

To solve for Th, we can rearrange the equation:

300.15/Th = 1 - 0.30

300.15/Th = 0.70

Cross-multiplying:

300.15 = 0.70 * Th

Dividing both sides by 0.70:

Th = 300.15 / 0.70

Calculating the value:

Th ≈ 428.79 K

Therefore, the temperature of the hot reservoir is approximately 428.79 Kelvin.

Please note that the calculations provided are based on the information given and the assumption that the heat engine is an ideal heat engine.