Question

Сколько стали можно расплавить, если передать ей 738 МДж?

Answer 1

Ответ:

Масса равна  9 тонн

Объяснение:

Дано:

Q = 738 МДж = 738·10⁶ Дж

λ = 0,82·10⁵ Дж/кг

____________

m - ?

Из формулы:

Q = λ·m

находим массу:

m = Q / λ

m = 738·10⁶ / (0,82·10⁵) ≈ 9 000 кг   или

m = 9 тонн

Answer 2

Calculating the Amount of Steel that Can be Melted with 738 MJ of Energy

To calculate the amount of steel that can be melted with 738 MJ of energy, we can use the specific heat capacity of steel and the heat of fusion of steel.

Specific Heat Capacity of Steel: The specific heat capacity of steel is approximately 0.466 J/g°C.

Heat of Fusion of Steel: The heat of fusion of steel is approximately 270 kJ/kg.

Calculation:

1. First, we need to convert the given energy from megajoules (MJ) to joules (J) as follows: - 1 MJ = 1,000,000 J - 738 MJ = 738,000,000 J

2. Next, we can calculate the amount of steel that can be melted using the formula: \[ \text{Amount of steel (in kg)} = \frac{\text{Energy (in J)}}{\text{Heat of Fusion (in J/kg)}} \]

Substituting the given values: \[ \text{Amount of steel (in kg)} = \frac{738,000,000 \, \text{J}}{270,000 \, \text{J/kg}} \]

Solving for the amount of steel: \[ \text{Amount of steel (in kg)} \approx 2733.33 \, \text{kg} \]

Conclusion:

With 738 MJ of energy, approximately 2733.33 kilograms of steel can be melted.

Please note that the above calculation provides an approximate value and actual results may vary based on specific conditions and properties of the steel being melted.