
Опори 2 Ом і 6 Ом з'єднані послідовно. Напруга на другому опорі 12 В. Якою є напруга на першому
опорі та сила струму?

Ответы на вопрос

Ответ: 4В
Объяснение:
Дано:
R1=2 Ом
R2=6 Ом
U2=12В
-------------
U1-?
I1=I2=I=U2/R2=12/6=2А
U1=I1*R1=2*2=4В



Calculation of Voltage and Current in a Series Circuit
In a series circuit with resistors of 2 ohms and 6 ohms connected in series, and a voltage of 12 volts across the second resistor, we can calculate the voltage across the first resistor and the current flowing through the circuit.
1. Voltage Across the First Resistor: - The total voltage in a series circuit is the sum of the voltages across each resistor. - Let's denote the voltage across the first resistor as V1 and the voltage across the second resistor as V2. - The total voltage (V_total) is equal to V1 + V2. - Given V2 = 12V, we can calculate V1 using the formula V1 = V_total - V2.
2. Current Through the Circuit: - In a series circuit, the same current flows through each resistor. - We can use Ohm's law, V = I * R, to calculate the current (I) flowing through the circuit.
Let's calculate the values using the given information.
Calculation Steps
1. Voltage Across the First Resistor (V1): - V_total = V1 + V2 - V1 = V_total - V2 - Substituting the values, V_total = 12V + V12. Current Through the Circuit (I): - We can use the formula V = I * R, where V is the total voltage and R is the total resistance in the circuit.
Calculation Results
1. Voltage Across the First Resistor (V1): - V1 = V_total - V2 - V1 = 12V - 12V - V1 = 0V2. Current Through the Circuit (I): - Total resistance (R_total) = 2 ohms + 6 ohms = 8 ohms - Using V = I * R, I = V_total / R_total - I = 12V / 8 ohms - I = 1.5 amperes
Therefore, the voltage across the first resistor is 0V and the current through the circuit is 1.5 amperes.


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