Question

!!!СРОЧНО!!! В сообщающиеся сосуды налили воду, и ртуть. Высота ртути 20см, определите высоту воды, если жидкости находятся в равновесии.

Answer 1

Ответ:

h₁ = 2,72 м

Объяснение:

Дано:

h₂ = 20 см = 0,2 м - высота столба ртути

ρ₁ = 1000 кг/м³ - плотность воды

ρ₂ = 13 600 кг/м³ - плотность ртути

_______________

h₁ - искомая высота столба воды

Решение:

ρ₁ / ρ₂ = h₂ / h₁

h₁ = ρ₂h₂ / ρ₁

h₁ = 13 600 * 0,2 / 1 000 = 2,72 м

Answer 2

Calculating the Height of Water in Equilibrium with Mercury

To calculate the height of water in equilibrium with mercury when both liquids are poured into communicating vessels, we can use the principle of communicating vessels, which states that the pressure at any point in a fluid at rest is the same at all points at the same height.

Given: - Height of mercury (h) = 20 cm

Using the principle of communicating vessels, the height of the water can be calculated using the formula:

h_water = h_mercury * (density_mercury / density_water)

Where: - h_water is the height of the water - h_mercury is the height of the mercury - density_mercury is the density of mercury - density_water is the density of water

Calculating the Height of Water

Using the provided information, we can calculate the height of the water in equilibrium with the mercury.

From Source we find the density of mercury (ρ_mercury) to be approximately 13.6 g/cm³, and the density of water (ρ_water) is approximately 1 g/cm³.

Plugging these values into the formula:

h_water = 20 cm * (13.6 g/cm³ / 1 g/cm³)

h_water = 20 cm * 13.6

h_water = 272 cm

Therefore, the height of the water in equilibrium with the mercury is approximately 272 cm.