Question

провідники опір яких 5 ом та 10 ом з'єднані паралельно. що можна сказати про силу струму, що протікає через кожен із них?

Answer 1

То що на першем провіднику струм буде в два разу більше ніж нам другом(I₁=2I₂), тому що при  паралельному підключенні напруг у кожного проводніка буде однаковим але опір відризняться в 2 разу у другого більше( R₂=2R₁)

Answer 2

Calculation of Current in Parallel Resistors

When two resistors are connected in parallel, the total resistance of the circuit can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

where R_total is the total resistance and R1 and R2 are the resistances of the individual resistors.

In this case, we have two resistors with resistances of 5 ohms and 10 ohms connected in parallel. Using the formula above, we can calculate the total resistance:

1/R_total = 1/5 + 1/10

Simplifying the equation:

1/R_total = 2/10 + 1/10 = 3/10

Taking the reciprocal of both sides:

R_total = 10/3 ohms

So, the total resistance of the circuit is 10/3 ohms.

Current through Each Resistor

According to Ohm's Law, the current flowing through a resistor is equal to the voltage across the resistor divided by its resistance. In a parallel circuit, the voltage across each resistor is the same.

Let's assume that the voltage across the resistors is V volts. The current flowing through each resistor can be calculated using Ohm's Law:

I1 = V / R1

I2 = V / R2

Substituting the given resistance values:

I1 = V / 5

I2 = V / 10

Since the voltage across both resistors is the same, we can equate the two equations:

V / 5 = V / 10

Cross-multiplying:

2V = V

Simplifying:

V = 0

This means that the voltage across the resistors is zero, and consequently, the current flowing through each resistor is also zero.

Therefore, in this specific case, when two resistors with resistances of 5 ohms and 10 ohms are connected in parallel, the current flowing through each resistor is zero.