Question

Два проводника сопротивлением r1=5 Ом и r2= 20 Ом соеденены параллельно. Напрчжение на проводниках 4В. Чему равна сила тока в общей цепи?

Answer 1

Ответ:

Общее сопротивление будет равно r1*r2/r1+r2=5*20/5+20=100/25=4 Ом

сила тока равна напряжение делить на сопротивление

4/4=1 А

Объяснение:

Когда проводники соединены параллельно, то напряжение на них равное, а сила тока общая равняется сумме

I1=U/R1=4/5=0,8 A

I2=U/R2=4/20=0,2 A

1 A=1A

В общей цепи 1 А.

думаю так. есть ответ?)

Answer 2

Calculating Total Current in the Circuit

To calculate the total current in the circuit, we can use the formula for the total resistance in a parallel circuit and Ohm's law.

The formula for the total resistance in a parallel circuit is given by:

1/R_total = 1/r1 + 1/r2

Where r1 and r2 are the resistances of the two conductors.

Given: - r1 = 5 Ω - r2 = 20 Ω

Using the formula, we can calculate the total resistance:

1/R_total = 1/5 + 1/20

1/R_total = 4/20 + 1/20

1/R_total = 5/20

1/R_total = 1/4

R_total = 4 Ω

Now, we can use Ohm's law to find the total current in the circuit. Ohm's law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R).

The formula for current (I) is given by:

I = V/R

Where: - V is the voltage across the conductors (given as 4V) - R is the total resistance (calculated as 4 Ω)

Substituting the values, we get:

I = 4V / 4Ω

I = 1A

Therefore, the total current in the circuit is 1A.