Question

Недавно просил помощи, но имею.гаглость спросить ещё раз. В общем вот: Тело объемом 0,0036 м3 имеет массу 15 кг. Какая сила потребуется, чтобы удержать это тело в воде?

Answer 1

Ответ:

V=0,0036м3

масса=15 кг

F=?

Объяснение:

F=mg= 15*1000= 15*10^3 Н

вроде так сори если не правильно))(

Answer 2

Calculating the Force Required to Hold the Object in Water

To calculate the force required to hold the object in water, we can use the concept of buoyancy. The force required to hold the object in water is equal to the weight of the water displaced by the object. This can be calculated using the formula:

F = ρ * V * g

Where: - F is the force required to hold the object in water - ρ is the density of water - V is the volume of the object - g is the acceleration due to gravity

Calculating the Volume of Water Displaced

First, let's calculate the volume of water displaced by the object. The volume of water displaced is equal to the volume of the object, which is given as 0.0036 m^3.

Calculating the Force

Next, we can calculate the force required to hold the object in water using the formula mentioned earlier. The density of water is approximately 1000 kg/m^3, and the acceleration due to gravity is approximately 9.81 m/s^2.

F = 1000 kg/m^3 * 0.0036 m^3 * 9.81 m/s^2

Now, let's calculate the force: ``` F = 1000 * 0.0036 * 9.81 F ≈ 35.28 N ```

Answer

The force required to hold the object in water is approximately 35.28 Newtons.