Question

Под действием какой ускоряющей разности потенциалов электрон приобретет скорость 200 км/с.

Answer 1

Объяснение:

A=q*U=1,6*10^-19*200=32*10^-18 Дж

Работа поля равна кинетической энергии A=Ek=m*V^2/2

V=sqrt(2*Ek/m)=sqrt(2*32*10^-18/9,1*10^-31)=8,38*10^6 м/с

Answer 2

Calculating the Potential Difference for an Electron to Reach a Speed of 200 km/s

To calculate the potential difference required for an electron to acquire a speed of 200 km/s, we can use the formula for kinetic energy and the relationship between kinetic energy and potential difference.

The kinetic energy of an electron can be calculated using the formula: K.E. = 0.5 * m * v^2 Where: - K.E. = Kinetic Energy - m = Mass of the electron - v = Velocity of the electron

The potential difference (V) required for the electron can be calculated using the relationship between kinetic energy and potential difference: K.E. = e * V Where: - e = Charge of the electron - V = Potential Difference

By equating the two formulas and solving for V, we can find the potential difference required for the electron to reach a speed of 200 km/s.

Calculation

Using the given speed of 200 km/s for the electron, we can calculate the potential difference required.

Given: - Speed of the electron (v) = 200 km/s - Mass of the electron (m) = 9.11 x 10^-31 kg - Charge of the electron (e) = 1.6 x 10^-19 C

Using the formula K.E. = 0.5 * m * v^2, we can calculate the kinetic energy of the electron. Then, using the relationship K.E. = e * V, we can solve for the potential difference (V).

Solution

Using the given values and the formulas, the potential difference (V) required for the electron to reach a speed of 200 km/s can be calculated as follows:

Step 1: Calculate Kinetic Energy (K.E.) - K.E. = 0.5 * m * v^2 - K.E. = 0.5 * (9.11 x 10^-31 kg) * (200,000 m/s)^2 - K.E. = 0.5 * (9.11 x 10^-31) * (4 x 10^7) - K.E. = 1.82 x 10^-31 * 4 x 10^7 - K.E. = 7.28 x 10^-24 J

Step 2: Calculate Potential Difference (V) - K.E. = e * V - V = K.E. / e - V = (7.28 x 10^-24 J) / (1.6 x 10^-19 C) - V ≈ 4.55 x 10^-6 V

Conclusion

Therefore, the potential difference required for an electron to acquire a speed of 200 km/s is approximately 4.55 x 10^-6 V.