Question

Об’єм водню за тиску 0,96·105 Па дорівнює 5 м3. Який об’єм буде мати водень за тиску 0,8·105 Па, якщо температура газу не змінювалася?

Answer 1

Ответ: 6 м³

Объяснение: Див. додаток

Answer 2

Calculation of Hydrogen Volume at Different Pressures

To calculate the volume of hydrogen at a different pressure, we can use the ideal gas law formula:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles of gas - R = ideal gas constant - T = temperature in Kelvin

Given: - Initial pressure (P1) = 0.96 * 10^5 Pa - Initial volume (V1) = 5 m^3 - Final pressure (P2) = 0.8 * 10^5 Pa - The temperature of the gas remains constant

We can use the formula to find the final volume (V2) of hydrogen at the new pressure.

Calculation Steps

1. Convert the initial and final pressures to standard units (Pascals). 2. Use the initial and final pressures, along with the initial volume, to calculate the final volume of hydrogen.

Calculation

1. Convert the pressures to Pascals: - Initial pressure (P1) = 0.96 * 10^5 Pa = 96000 Pa - Final pressure (P2) = 0.8 * 10^5 Pa = 80000 Pa

2. Use the formula PV = nRT to find the final volume (V2) of hydrogen: - Since the temperature remains constant, we can use the equation P1V1 = P2V2 - Solving for V2: V2 = (P1 * V1) / P2 - Substitute the values: V2 = (96000 * 5) / 80000 - V2 ≈ 6 m^3

The volume of hydrogen at a pressure of 0.8 * 10^5 Pa, with the temperature of the gas remaining constant, will be approximately 6 m^3.