Question

під час спуску з гори швидкість велосипедиста масою 50 кг, що рухається рівноприскорено збільшилась з 18км/год до 36 км/год за 5 сек. визначити рівнодійну сил,що діють на нього​

Answer 1

Ответ:

Объяснение:

m = 50 кг

V1 = 18км/год = 5 м/с

V2 = 36 км/год = 10 м/с

t =  5 сек.

F = ?

a = (V2-V1) / t = (10-5) / 5 = 1 м/с^2

F = m*a = 50*1 = 50 H

Answer 2

Calculation of Net Force on the Cyclist

To calculate the net force acting on the cyclist, we can use the equation:

Net Force = Mass x Acceleration

First, let's calculate the acceleration of the cyclist using the change in velocity and the time taken.

Given: - Initial velocity (u) = 18 km/h - Final velocity (v) = 36 km/h - Time taken (t) = 5 seconds

We need to convert the velocities from km/h to m/s for consistency. 1 km/h is equal to 0.27778 m/s.

So, the initial velocity (u) = 18 km/h = 18 x 0.27778 m/s = 5 m/s And the final velocity (v) = 36 km/h = 36 x 0.27778 m/s = 10 m/s

Now, we can calculate the acceleration (a) using the formula:

Acceleration = (Change in Velocity) / Time taken

Acceleration = (v - u) / t

Acceleration = (10 m/s - 5 m/s) / 5 s = 5 m/s / 5 s = 1 m/s²

Now that we have the acceleration, we can calculate the net force acting on the cyclist using the given mass of 50 kg:

Net Force = Mass x Acceleration

Net Force = 50 kg x 1 m/s² = 50 N

So, the net force acting on the cyclist is 50 Newtons.