Question

ДАЮ МНОГО БАЛОВ!!!!! Визначте прискорення реактивного лайнера під час зльоту, якщо його маса 167 т, сила тяги двигунів 225 кН, а коефіцієнт тертя коліс шасі об злітну смугу 0,02 ПОМОГИТЕ!!!! С дано і формулами!!!!​

Answer 1

Ответ: 1,15 м/с²

Объяснение:

Answer 2

Ответ:

Объяснение:

m = 167 т = 167000 кг

F1 =  225 кН = 225000 H

μ =  0,02

a = ?

Fтр = INI*μ = m*g*μ

F = F1 - Fтр  = m*a

a = (F1 - m*g*μ) / m = (F1/m) - g*μ =

= (225000 / 167000) - 10*0.02 == 1.15 м/с^2

Answer 3

It looks like you're asking for help with a physics problem related to the acceleration of a jetliner during takeoff. I'd be happy to assist you with that! Let's break down the problem step by step.

Given Parameters:

- Mass of the jetliner (m): 167 tons - Thrust force of the engines (F): 225 kN - Coefficient of friction of the wheels on the runway (μ): 0.02

Formulas Used:

The acceleration of the jetliner during takeoff can be calculated using the following formula: a = (F - μmg) / m Where: - a = acceleration - F = thrust force of the engines - μ = coefficient of friction - m = mass of the jetliner - g = acceleration due to gravity (approximately 9.81 m/s^2)

Calculation:

Let's plug in the given values into the formula: a = (225,000 N - 0.02 * 167,000 kg * 9.81 m/s^2) / 167,000 kg

Now, let's calculate the acceleration using the given values: a ≈ (225,000 - 32,734.8) / 167,000 a ≈ 192,265.2 / 167,000 a ≈ 1.149 m/s^2

So, the acceleration of the jetliner during takeoff is approximately 1.149 m/s^2.

I hope this helps! If you have any more questions or need further assistance, feel free to ask.