Question

Три резистори опорами 2 Ом кожен, з"єднані послідовно і приєднані до джерела живлення 12 В Який опір кола та сила струму в ньому?​

Answer 1

Відповідь:

2A

Пояснення:

R∑=R1*3=2*3=6 Om

I=U/R∑⇒12/6=2

Answer 2

Calculation of the Total Resistance and Current in the Circuit

To calculate the total resistance and current in the circuit, we need to consider the three resistors connected in series and the given power supply voltage.

Given: - Each resistor has a resistance of 2 Ω. - The resistors are connected in series. - The power supply voltage is 12 V.

To find the total resistance in a series circuit, we add up the individual resistances. In this case, since all three resistors have the same resistance of 2 Ω, the total resistance can be calculated as follows:

Total Resistance (R_total) = Resistance of Resistor 1 + Resistance of Resistor 2 + Resistance of Resistor 3

R_total = 2 Ω + 2 Ω + 2 Ω = 6 Ω

Therefore, the total resistance of the circuit is 6 Ω.

To find the current flowing through the circuit, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R):

Current (I) = Voltage (V) / Resistance (R)

I = 12 V / 6 Ω = 2 A

Therefore, the current flowing through the circuit is 2 A.

In summary, the circuit has a total resistance of 6 Ω and a current of 2 A.