Question

Q1=5нКлq2=6нКлF=0,12мНr-?

Answer 1

F=kq1q2/r^2
r=√kq1q1/r=√9×10^9×5×10^-9×6×10^-9/0,12×10^-3=√270×10^-9/0,12×10^-3=√2250×10^-6=47,4×10^-3

Answer 2

To find the value of 'r' in the equation F = k * (q1 * q2) / r^2, where q1 = 5 nC, q2 = 6 nC, and F = 0.12 mN, we need to know the value of the electrostatic constant 'k'.

The electrostatic constant, also known as Coulomb's constant, is approximately equal to 9 × 10^9 N m^2/C^2.

Substituting the given values into the equation, we have:

0.12 mN = (9 × 10^9 N m^2/C^2) * ((5 × 10^-9 C) * (6 × 10^-9 C) / r^2)

Simplifying further:

0.12 mN = (9 × 10^9 N m^2/C^2) * (30 × 10^-18 C^2 / r^2)

Converting millinewtons (mN) to newtons (N):

0.12 × 10^-3 N = (9 × 10^9 N m^2/C^2) * (30 × 10^-18 C^2 / r^2)

0.12 × 10^-3 N = (9 × 30) * (10^9 N m^2/C^2) * (10^-18 C^2 / r^2)

0.12 × 10^-3 N = 270 × 10^-9 N m^2 / r^2

Dividing both sides by 270 × 10^-9 N m^2:

r^2 = (270 × 10^-9 N m^2) / (0.12 × 10^-3 N)

r^2 = 2250 m^2

Taking the square root of both sides:

r = √(2250 m^2)

r ≈ 47.43 m

Therefore, the approximate value of 'r' is 47.43 meters.