Question

Длина прямоугольника 7см а ширина на 2 см меньше. Найти периметр и площадь.

Answer 1

1) 7-2=5(см) ширина
2) (7+5) ×2=24(см) P
3) 7×5=35(см2) S
Ответ: S=35см2, P=24 см

Answer 2

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Answer 3

Problem Analysis

We are given the length of a rectangle as 7 cm and the width as 2 cm less than the length. We need to find the perimeter and area of the rectangle.

Calculation

To find the perimeter of a rectangle, we add the lengths of all four sides. The formula for the perimeter of a rectangle is:

Perimeter = 2 * (Length + Width)

Substituting the given values, we have:

Perimeter = 2 * (7 cm + (7 cm - 2 cm))

Simplifying the expression, we get:

Perimeter = 2 * (7 cm + 5 cm) = 2 * 12 cm = 24 cm To find the area of a rectangle, we multiply the length by the width. The formula for the area of a rectangle is:

Area = Length * Width

Substituting the given values, we have:

Area = 7 cm * (7 cm - 2 cm)

Simplifying the expression, we get:

Area = 7 cm * 5 cm = 35 cm^2

Answer

Therefore, the perimeter of the rectangle is 24 cm and the area of the rectangle is 35 cm^2.