Question

С двух пунктов расстояния между которыми 210 км вышли одновременно навстречу друг к другу 2 поезда . скорость первого на 5 км/год больше скорости другого. найдите скорость каждого поезда, если они встретились через 2 часа.

Answer 1

210:2=105 км/час скорость сближения
105-5=100 км\час скорость сближения без разницы
10062=50 км/час скорость первого
50=5=55 км\час скорость второго
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Answer 2

Problem Analysis

We are given that two trains start from points that are 210 km apart and travel towards each other. The first train has a speed that is 5 km/h faster than the second train. We need to find the speed of each train if they meet after 2 hours.

Solution

Let's assume the speed of the second train is x km/h. Then, the speed of the first train will be x + 5 km/h.

We know that the distance traveled by a train is equal to the product of its speed and time. So, the distance traveled by the first train in 2 hours is (x + 5) * 2 km, and the distance traveled by the second train in 2 hours is x * 2 km.

Since the two trains are traveling towards each other, the sum of their distances traveled should be equal to the total distance between them, which is 210 km.

Therefore, we can write the equation:

(x + 5) * 2 + x * 2 = 210

Simplifying the equation:

2x + 10 + 2x = 210

4x + 10 = 210

4x = 200

x = 50

The speed of the second train is 50 km/h, and the speed of the first train is 55 km/h.

Answer

The speed of the first train is 55 km/h, and the speed of the second train is 50 km/h.