Question

В одном баке было 140 л воды, а в другом-108 л.Из первого бака за 1 час выливается 5 л воды,тз второго 6 л.Одновременно открыли оба бака.Через сколько часов во втором баке воды окажется в 2,5 раза меньше ,чем в первом?

Answer 1

Ответ через 13 минут
Составляем уравнениех- время в минутах 140-5х - остается воды в 1 баке108-6х - во 2 баке
(140-5х) /(108-6х) = 2,5140-5х=270--15х15х-5х=270-14010х=130х=13

Answer 2

Problem Analysis

We have two tanks, one with 140 liters of water and the other with 108 liters of water. From the first tank, 5 liters of water are poured out every hour, and from the second tank, 6 liters of water are poured out every hour. We want to find out how many hours it will take for the amount of water in the second tank to be 2.5 times less than the amount of water in the first tank.

Solution

To solve this problem, we can set up an equation based on the given information and solve for the unknown variable, which is the number of hours it will take for the amount of water in the second tank to be 2.5 times less than the amount of water in the first tank.

Let's denote the number of hours as h.

The amount of water in the first tank after h hours can be calculated as: Amount in first tank = 140 - 5h

The amount of water in the second tank after h hours can be calculated as: Amount in second tank = 108 - 6h

According to the problem, we want the amount of water in the second tank to be 2.5 times less than the amount of water in the first tank. Mathematically, this can be expressed as: Amount in second tank = 2.5 * (Amount in first tank)

Substituting the expressions for the amount of water in the first and second tanks, we get: 108 - 6h = 2.5 * (140 - 5h)

Now, we can solve this equation to find the value of h.

Calculation

Let's solve the equation:

108 - 6h = 2.5 * (140 - 5h)

Expanding the right side of the equation: 108 - 6h = 350 - 12.5h

Combining like terms: 12.5h - 6h = 350 - 108 6.5h = 242

Dividing both sides by 6.5: h = 242 / 6.5 h ≈ 37.23

Answer

It will take approximately 37.23 hours for the amount of water in the second tank to be 2.5 times less than the amount of water in the first tank.

Please note that the calculated value is an approximation and may not be an exact integer value.

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