Question

При сложении двух натуральных чисел Вася ошибочно поставил лишний нуль в конце одного из слагаемых и получил в сумме 6946 вместо 3166.Какие числа он складывал. решити пожалуста очень надо

Answer 1

Пусть х - первое число, а  - второе число, тогда их сумма = 3166

x+y=3166

лишний нуль в конце одного из слагаемых означает, что xисло умножили на 10. вот пусть второе число y умножили на 10, т.е. 10y, тогда сумма первого числа и второго = 6946 

x+10y=6946

 

x=3166-y

3166-y+10y=6946

9y=3780

y=420

x=3166-420= 2746

 

Ответ: 420 и 2746

 

Answer 2

Problem Analysis

Vasya made a mistake while adding two natural numbers and accidentally added an extra zero at the end of one of the addends. The sum he obtained was 6946 instead of 3166. We need to determine the two numbers he was adding.

Solution

To find the two numbers Vasya was adding, we can subtract the smaller number from the larger number. The difference between the two numbers will be the number that Vasya mistakenly added an extra zero to.

Let's assume the two numbers Vasya was adding are A and B, where A is the number with the extra zero. We can set up the following equation:

A + B = 6946 (Equation 1)

We also know that the correct sum of the two numbers should be 3166. So we can set up another equation:

A + B = 3166 (Equation 2)

By subtracting Equation 2 from Equation 1, we can eliminate the variable B:

(A + B) - (A + B) = 6946 - 3166

0 = 3780

Since the equation is not true, it means that our assumption was incorrect. There is no solution to this problem.

Conclusion

There is no solution to the problem because the given sum of 6946 cannot be obtained by adding two natural numbers, one of which has an extra zero at the end.