Question

Периметр прямоугольника40 чему равна площадь этого прямоугольника если его длина больше ширины в з раза

Answer 1

Пусть а-длина,в-ширина,то периметр=2(а+в),т.к3в=а,то
40=2(3в+в)
8в=40
в=5, тогда а=3*5=15,то
s=15*5=75

Answer 2

Calculation of the Perimeter and Area of a Rectangle

To find the perimeter and area of a rectangle, we need to know the length and width of the rectangle. Let's assume the length of the rectangle is L and the width is W. The perimeter of a rectangle is given by the formula:

Perimeter = 2(L + W) Given that the perimeter of the rectangle is 40, we can set up the equation:

40 = 2(L + W)

Simplifying the equation, we have:

L + W = 20 (Equation 1)

We are also given that the length of the rectangle is Z times greater than the width. Mathematically, we can express this as:

L = ZW (Equation 2)

Substituting Equation 2 into Equation 1, we get:

ZW + W = 20

Factoring out the common factor of W, we have:

W(Z + 1) = 20

Solving for W, we