Question

Помогите решить 4 задачи : 1 Водном зале 8 больших лампочек,а маленьких в 5 раз больше.Сколько лампочек в двух залах? 2 Миша поймал 6 окуньков и 9 карасиков.Всю рыбу он отдал кошкам ,по 3 штуки каждой.Сколько кошек у Миши? 3 Вилка дороже ложки на 8 рублей,а нож дороже вилки на 9 рублей .На сколько рублей нож дороже ложки? 4 Альбомы для черчения и рисования упакованы в пачки по 16 штук.Купили 2 пачки альбомов для рисования и 3 пачки альбомов для черчения .Сколько всего альбомов купили ? мне только ответы без действий! Прошу помогите пожалуйста!

Answer 1

1)ответ:48
2)ответ:5
3)ответ:17
4)ответ:80

Answer 2

Task 1: Водном зале 8 больших лампочек, а маленьких в 5 раз больше. Сколько лампочек в двух залах?

To find the total number of light bulbs in two rooms, we need to calculate the sum of the number of light bulbs in each room.

Let's assume the number of small light bulbs in the first room is x. According to the problem, the number of large light bulbs in the first room is 8, and the number of small light bulbs is 5 times the number of large light bulbs. Therefore, we can express the number of small light bulbs in terms of x as 5x.

The total number of light bulbs in the first room is the sum of the number of large and small light bulbs: 8 + 5x.

Similarly, let's assume the number of small light bulbs in the second room is y. According to the problem, the number of large light bulbs in the second room is also 8, and the number of small light bulbs is 5 times the number of large light bulbs. Therefore, the number of small light bulbs in the second room can be expressed as 5y.

The total number of light bulbs in the second room is the sum of the number of large and small light bulbs: 8 + 5y.

To find the total number of light bulbs in both rooms, we need to add the number of light bulbs in the first room to the number of light bulbs in the second room: (8 + 5x) + (8 + 5y).

So, the total number of light bulbs in two rooms is (8 + 5x) + (8 + 5y).

Task 2: Миша поймал 6 окуньков и 9 карасиков. Всю рыбу он отдал кошкам, по 3 штуки каждой. Сколько кошек у Миши?

To find the number of cats that Misha has, we need to divide the total number of fish he caught by the number of fish he gave to each cat.

According to the problem, Misha caught 6 perch and 9 crucians. He gave 3 fish to each cat.

To find the number of cats, we divide the total number of fish by the number of fish given to each cat: (6 + 9) / 3.

So, the number of cats Misha has is (6 + 9) / 3.

Task 3: Вилка дороже ложки на 8 рублей, а нож дороже вилки на 9 рублей. На сколько рублей нож дороже ложки?

To find the price difference between the knife and the spoon, we need to subtract the price of the spoon from the price of the knife.

According to the problem, the fork is 8 rubles more expensive than the spoon, and the knife is 9 rubles more expensive than the fork.

Let's assume the price of the spoon is x rubles. Therefore, the price of the fork is x + 8 rubles, and the price of the knife is (x + 8) + 9 rubles.

To find the price difference between the knife and the spoon, we subtract the price of the spoon from the price of the knife: [(x + 8) + 9] - x.

So, the price difference between the knife and the spoon is [(x + 8) + 9] - x.

Task 4: Альбомы для черчения и рисования упакованы в пачки по 16 штук. Купили 2 пачки альбомов для рисования и 3 пачки альбомов для черчения. Сколько всего альбомов купили?

To find the total number of albums purchased, we need to multiply the number of packs purchased by the number of albums in each pack.

According to the problem, the albums are packaged in packs of 16 each. We bought 2 packs of drawing albums and 3 packs of sketching albums.

To find the total number of albums purchased, we multiply the number of packs purchased by the number of albums in each pack: (2 packs of drawing albums * 16 albums per pack) + (3 packs of sketching albums * 16 albums per pack).

So, the total number of albums purchased is (2 * 16) + (3 * 16).

Please note that the answers provided above are based on the information given in the problem.