Question

Одна бригада может собрать урожай за 8 дней, а другая -за 6 дней.за какое время , работая вместе, бригады соберут7 /8 урожая? Решите пожалуйста за ближайшие 10 минут , заранее спасибо за решение задачи вознаграждение

Answer 1

1/8 - производительность одной бригады
1/6 производительность второй бригады
1/8 + 1/6 = 3/24 + 4/24 = 7/24 совместная производительность бригад
7/8 : 7/24 = 7/8 * 24/7 = 1/1 * 3/1 = 3 дня
За 3 дня соберут они вместе урожай 7/8

Answer 2

To solve this problem, we can use the concept of work rates. Let's assume that the first brigade's work rate is represented by "x" (in terms of fraction of the harvest they can complete per day) and the second brigade's work rate is represented by "y".

According to the problem, the first brigade can complete the entire harvest in 8 days, so their work rate is 1/8 of the harvest per day. Similarly, the second brigade can complete the entire harvest in 6 days, so their work rate is 1/6 of the harvest per day.

To find out how long it will take for both brigades to complete 7/8 of the harvest when working together, we need to add their work rates. So the combined work rate is x + y.

We can set up the following equation to represent the situation:

(x + y) * t = 7/8

Where "t" represents the time it takes for both brigades to complete 7/8 of the harvest.

Now, let's solve this equation to find the value of "t".

Solving the equation:

(x + y) * t = 7/8

We know that x = 1/8 and y = 1/6.

Substituting these values into the equation:

(1/8 + 1/6) * t = 7/8

To add the fractions, we need to find a common denominator, which is 24 in this case.

(3/24 + 4/24) * t = 7/8

Simplifying the left side of the equation:

(7/24) * t = 7/8

To isolate "t", we can multiply both sides of the equation by the reciprocal of (7/24), which is (24/7).

t = (7/8) * (24/7)

Simplifying further:

t = 3

Therefore, when working together, the brigades will be able to complete 7/8 of the harvest in 3 days.

Please note that this solution assumes that the work rates of the brigades remain constant throughout the entire duration of the task.