Question

В одному ящику було в 7 разів більше апельсинів ніж у другому. Коли з першого ящика взяли 38 апельсинів а з другого 14 тов другому залишилось на 78 апельсинів менше ніж у першому. Скільки апельсинів було в кожному ящику спочатку. начертите пж схему ес что могу помоч с инфой и англ

Answer 1

7x-38=(x-14)+78
7x-x=78-14+38
6x=102
x=17кг в другому ящику
в першому 7*17=119кг
Відповідь:119кг і 17 кг.

Answer 2

Problem Analysis

We are given two boxes of oranges, where one box has 7 times more oranges than the other. After taking 38 oranges from the first box and 14 oranges from the second box, there were 78 fewer oranges in the second box compared to the first box. We need to determine the initial number of oranges in each box.

Solution

Let's assume the initial number of oranges in the first box is x and in the second box is y.

According to the given information, we can set up the following equations:

1. The first box has 7 times more oranges than the second box: x = 7y. 2. After taking 38 oranges from the first box and 14 oranges from the second box, there were 78 fewer oranges in the second box compared to the first box: y - 14 = (x - 38) - 78.

Now, let's solve these equations to find the values of x and y.

Substituting the value of x from equation 1 into equation 2, we get:

y - 14 = (7y - 38) - 78

Simplifying the equation:

y - 14 = 7y - 38 - 78

y - 14 = 7y - 116

6y = 102

y = 17

Substituting the value of y into equation 1, we get:

x = 7 * 17

x = 119

Therefore, there were initially 119 oranges in the first box and 17 oranges in the second box.

Diagram

Here's a diagram to illustrate the problem:

First Box: 119 oranges
Second Box: 17 oranges

I hope this helps! Let me know if you have any further questions.