Question

В двух цистернах было поровну воды.Когда из 1-ой цистерны взяли 54 л воды, а из 2-ой 6 л, то в 1-ой цистерне осталось в 4 раза меньше, чем во второй. Сколько было в каждой цистерне вначале?

Answer 1

Пусть х л воды было в каждой цистерне первоначально, тогда
(х-54) л воды стало в первой цистерне, а 
(х-6) л воды стало во второй цистерне.
Т.К. в первой стало в 4 раза меньше, чем во второй, то составим уравнение: 4(х-54)=х-6,  4х-216-х+6+0;  3х=210;  х=70
Ответ: в цистернах было по 70л воды

Answer 2

Initial State of the Tanks

Let's denote the initial amount of water in the first tank as x liters and in the second tank as y liters.

Water Taken Out

From the first tank, 54 liters of water were taken out, and from the second tank, 6 liters were taken out.

Remaining Water

After the water was taken out, the first tank had 4 times less water than the second tank.

Equation Setup

We can set up the following equations based on the given information: 1. x - 54 = 4(y - 6) (The remaining water in the first tank is 4 times less than the remaining water in the second tank) 2. x = y + 48 (The amount of water taken out from the first tank is 54 liters, and from the second tank is 6 liters)

Solving the Equations

We can solve the system of equations to find the initial amounts of water in each tank.

Solution

Using the second equation, we can express y in terms of x: y = x - 48

Substitute y in the first equation: x - 54 = 4((x - 48) - 6) x - 54 = 4x - 240 3x = 186 x = 62

Substitute x in the second equation to find y: y = 62 - 48 y = 14

So, initially, there were 62 liters of water in the first tank and 14 liters of water in the second tank.