Question

Вечером в столовой осталось 5 котлет, в одной из них застряла муха. Коля берет на ужин две котлеты. Какова вероятность того, что ему достанется котлета с мухой?

Answer 1

Вероятность события А "муха в первой котлете" = 1/5

вероятность события Б "мухи в первой нет, а во второй есть " = 4/5*1/4 = 1/5

вероятность события "А или Б" = 1/5+1/5 = 2/5

ответ 40%  

Answer 2

Probability of Getting a Patty with a Fly

To calculate the probability of Kolya getting a patty with a fly, we need to consider the total number of possible outcomes and the number of favorable outcomes.

Given that there are 5 patties left in the cafeteria, and one of them has a fly, the total number of possible outcomes is 5.

Kolya takes 2 patties for dinner. To calculate the number of favorable outcomes, we need to consider the different scenarios:

1. Kolya takes both patties without a fly: In this case, there are 4 patties left without a fly. 2. Kolya takes one patty without a fly and one patty with a fly: In this case, there is 1 patty left with a fly and 4 patties left without a fly.

Therefore, the number of favorable outcomes is 4 (scenario 1) + 1 (scenario 2) = 5.

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