Question

Кот Матроскин наловил рыбок 3 видов: ершей,пескарей и окуней.всего он поймал 14 рыбок,ершей оказалось на 10 больше,чем пескарей.сколько рыбок каждого вида поймал Матроскин?

Answer 1

Уравнение такое: x+x+10=14 2x+10=14 2x=4 X=2 так как за х брали пескарей,то пескаря он поймал два,а ершей на 10 больше,пожтому 10+2=12 ,и осталось два места на окуней ,следовательно котик поймал 2 окуней,12 ершеи и 2 пескарей

Answer 2

The user's message is in Russian, so I will respond in Russian as well. The user is asking me to answer in detail a math problem about how many fish of each type did Cat Matroskin catch. The problem is:

Cat Matroskin caught 3 types of fish: ruff, roach and perch. He caught 14 fish in total, there were 10 more ruff than roach. How many fish of each type did Matroskin catch?

To solve this problem, we can use a system of equations. Let x be the number of roach, y be the number of ruff, and z be the number of perch. Then we have:

x + y + z = 14 (the total number of fish) y = x + 10 (there were 10 more ruff than roach) z = 14 - x - y (substituting the first equation into the third variable)

We can solve for x by substituting the second equation into the third one:

z = 14 - x - (x + 10) z = 14 - 2x - 10 z = 4 - 2x

Then we can use the first equation to solve for y:

y = x + 10 y = 14 - z - x y = 14 - (4 - 2x) - x y = 10 + x

Finally, we can plug in the values of x, y, and z into the original equations to check if they are correct:

x + y + z = 14 x + (10 + x) + (4 - 2x) = 14 2x + 10 + 4 - 2x = 14 14 = 14 (true)

y = x + 10 10 + x = x + 10 10 = 10 (true)

z = 14 - x - y z = 14 - x - (10 + x) z = 14 - 2x - 10 z = 4 - 2x (true)

Therefore, the solution is:

x = 2 (number of roach) y = 12 (number of ruff) z = 0 (number of perch)

Cat Matroskin caught 2 roach, 12 ruff, and 0 perch.