
Три пирата вечером поделили добытые за день бриллианты: по двенадцать Биллу и Сэму, а остальные —
Джону, который считать не умел. Ночью Билл у Сэма, Сэм у Джона, а Джон у Билла украли по одному бриллианту. В результате средняя масса бриллиантов у Билла уменьшилась на один карат, у Сэма уменьшилась на два карата, зато у Джона увеличилась на четыре карата. Сколько бриллиантов досталось Джону?

Ответы на вопрос




Problem Analysis
Three pirates, Bill, Sam, and John, divided the diamonds they obtained during the day. Bill and Sam each received twelve diamonds, while the rest were given to John, who couldn't count. During the night, one diamond was stolen from Bill by Sam, one diamond was stolen from Sam by John, and one diamond was stolen from John by Bill. As a result, the average weight of the diamonds decreased by one carat for Bill, decreased by two carats for Sam, and increased by four carats for John. We need to determine how many diamonds John received.Solution
Let's assume the initial number of diamonds obtained by John is x.According to the given information: - Bill initially had 12 diamonds and lost one to Sam during the night. - Sam initially had 12 diamonds and lost one to John during the night. - John initially had x diamonds and lost one to Bill during the night.
After the night, the average weight of the diamonds decreased by one carat for Bill, decreased by two carats for Sam, and increased by four carats for John.
Based on this information, we can set up the following equation:
(12 - 1) + (12 - 1) + (x - 1) = (12 - 1) - 1 + (12 - 2) - 2 + (x + 4) + 4
Simplifying the equation:
22 + x - 3 = 20 + x + 6
Simplifying further:
x - 3 = x + 6
Subtracting x from both sides:
-3 = 6
This equation is not possible, which means there is no solution that satisfies the given conditions. Therefore, we cannot determine how many diamonds John received.
Note: The given problem may have a logical error or inconsistency, as the equation derived from the given information leads to an impossible solution.
Please let me know if there's anything else I can help you with!


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