Question

Из города одновременно в одном и том же направлении выехали два мотоциклиста.Скорость первого из них была больше скорости второго и составляла 72 км/ч.Через 25 мин расстояние между мотоциклистами было равно 5 км.Найдите скорость второму мотоциклиста.

Answer 1

найдем расстояние,  пройденое 1-ым мотоциклистом 25 мин=2/12 часа

72*5/12=30км

30-5=25км-проехал второй

25:5/12=60 км/ч -скорость второго мотоциклиста

 

 

 

 

 

 

Answer 2

Problem Analysis

We are given that two motorcyclists start from the same city in the same direction. The speed of the first motorcyclist is 72 km/h, and after 25 minutes, the distance between the two motorcyclists is 5 km. We need to find the speed of the second motorcyclist.

Solution

Let's assume the speed of the second motorcyclist is x km/h.

We know that the distance covered by the first motorcyclist in 25 minutes (0.4167 hours) is equal to the distance covered by the second motorcyclist in the same time. Therefore, we can set up the following equation:

72 km/h * 0.4167 h = x km/h * 0.4167 h + 5 km

Simplifying the equation, we get:

30 km = 0.4167x km + 5 km

Subtracting 5 km from both sides, we get:

30 km - 5 km = 0.4167x km

25 km = 0.4167x km

Dividing both sides by 0.4167, we get:

x km/h = 25 km / 0.4167

Evaluating the expression, we find:

x ≈ 60 km/h

Therefore, the speed of the second motorcyclist is approximately 60 km/h.

Answer

The speed of the second motorcyclist is approximately 60 km/h.