
1)4x=7(2x-3)+46 2)15+6(3u+4)=0 3) 3(t-4)-6=5(t-3) Я решила все, но сомневаюсь в ответах, помогите
пожалуйста

Ответы на вопрос

4х=14х-21+46
4х-14х=25
-10х=25
х=25:(-10)
х=-2.5
2)15+6(3u+4)=0
15+18u+24=0
18u=-39
u=-39:18
u=-13\6=-2 1\6
3) 3(t-4)-6=5(t-3)
3t-12-6=5t-15
3t-5t=-15-18
-2t=-33
t=-33:(-2)
t=16 1\2=16.5



1) 4x=7(2x-3)+46
x=-5/2
2)15+6(3u+4)=0
u=-13/6
3)3(t-4)-6=5(t-3)
t=-3/2



Solution to Equation 1: 4x = 7(2x-3) + 46
To solve the equation 4x = 7(2x-3) + 46, we can follow these steps:
1. Distribute the 7 to the terms inside the parentheses: 4x = 14x - 21 + 46
2. Combine like terms: 4x = 14x + 25
3. Subtract 14x from both sides of the equation to isolate the variable: 4x - 14x = 25 -10x = 25
4. Divide both sides of the equation by -10 to solve for x: x = 25 / -10 x = -2.5
Therefore, the solution to the equation 4x = 7(2x-3) + 46 is x = -2.5.
Solution to Equation 2: 15 + 6(3u+4) = 0 + 3
To solve the equation 15 + 6(3u+4) = 0 + 3, we can follow these steps:
1. Distribute the 6 to the terms inside the parentheses: 15 + 18u + 24 = 3
2. Combine like terms: 18u + 39 = 3
3. Subtract 39 from both sides of the equation to isolate the variable: 18u = 3 - 39 18u = -36
4. Divide both sides of the equation by 18 to solve for u: u = -36 / 18 u = -2
Therefore, the solution to the equation 15 + 6(3u+4) = 0 + 3 is u = -2.
Solution to Equation 3: 3(t-4) - 6 = 5(t-3)
To solve the equation 3(t-4) - 6 = 5(t-3), we can follow these steps:
1. Distribute the 3 and 5 to the terms inside the parentheses: 3t - 12 - 6 = 5t - 15
2. Combine like terms: 3t - 18 = 5t - 15
3. Subtract 3t from both sides of the equation to isolate the variable: -18 = 2t - 15
4. Add 15 to both sides of the equation: -3 = 2t
5. Divide both sides of the equation by 2 to solve for t: t = -3 / 2 t = -1.5
Therefore, the solution to the equation 3(t-4) - 6 = 5(t-3) is t = -1.5.
I hope this helps! Let me know if you have any further questions.


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