Question

Расстояние между двумя велосипедистами 240 метров. Они выехали одновременно навстречу друг другу и встретились через 30 секунд. Найдите скорость первого велосипедиста, если скорость второго 3 метров в секунду

Answer 1

1)3*30=90(км)
2)240-90=150(км)
3)150:30=5(м/с)

Answer 2

Problem Analysis

We are given that two cyclists start simultaneously and ride towards each other. The distance between them is 240 meters, and they meet after 30 seconds. We are also given that the speed of the second cyclist is 3 meters per second. We need to find the speed of the first cyclist.

Solution

Let's assume the speed of the first cyclist is v1 meters per second. Since the cyclists are riding towards each other, their combined speed is the sum of their individual speeds. Therefore, the combined speed of the two cyclists is v1 + 3 meters per second.

We can use the formula distance = speed × time to find the distance traveled by each cyclist. The distance traveled by the first cyclist is v1 × 30 meters, and the distance traveled by the second cyclist is 3 × 30 meters.

Since the total distance between the two cyclists is 240 meters, we can set up the equation:

v1 × 30 + 3 × 30 = 240

Simplifying the equation:

30v1 + 90 = 240

Subtracting 90 from both sides:

30v1 = 150

Dividing both sides by 30:

v1 = 5

Therefore, the speed of the first cyclist is 5 meters per second.

Answer

The speed of the first cyclist is 5 meters per second.